-2x^2-12x-8=-x^2-8x-4

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Solution for -2x^2-12x-8=-x^2-8x-4 equation: 



-2x^2-12x-8=-x^2-8x-4

We move all terms to the left:

-2x^2-12x-8-(-x^2-8x-4)=0

We get rid of parentheses

-2x^2+x^2+8x-12x+4-8=0

We add all the numbers together, and all the variables

-1x^2-4x-4=0

a = -1; b = -4; c = -4;
Δ = b2-4ac
Δ = -42-4·(-1)·(-4)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{4}{-2}=-2$

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